Step 1, we choose a pivot, usually it is 1,1 and remove the other elemnts in the same column
Pivot cant be 0, but why
and if i find a 0 pivot i just re arrange the rows
Failure happens when i get a zero pivot and cant do a row exchange
Augemnted matrix: a matrix where i added stuff on it
Matrix multiplication is associative but not commutative


The last way is block by block
**
*o
E_21 means the matrix that would produce 0 in row 2 col 1

From my current understanding. in A = LU the A must be able to be eliminated without a row exchange
In the L we only get the multipliers, not other numbers like the 10 as in the lecture, We just know the multipliers so we dont have to recalcultate the whole matrix inverse. TODO: revise

Search on why we dont like the E’s
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